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Stels [109]
3 years ago
15

I need help for number 22.

Mathematics
1 answer:
boyakko [2]3 years ago
8 0
EHRP, EHFG, EFPQ  Does that make sense?
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Which equation can be used to find the number of fish in the pond on June 1?
olga_2 [115]

Answer: The required equation is f-52=63 and the number of fishes in the pond on June 1 = 115


Step-by-step explanation:

Given: The number of fishes in pond on July 1 = 63

Also, it is said that the number of fishes in pond on July 1 is 52 fewer(lesser) than the number of fishes in pond on June 1.

Let f be the number of fishes in pounds on June 1.

then the required equation will be

f-52=63

Now, add 52 on both the sides  of the equation, we get

f=63+52\\\Rightarrow\ f=115


3 0
3 years ago
10.
yan [13]

Answer:

D. y = -5^x – 27

Step-by-step explanation:

Find the negative reciprocal of the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line perpendicular to  − x + 5 y = 14 .

y = − 5 x − 27                         PERPENDICULAAR

...................................................................................................................................................

Find the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line parallel to  − x + 5 y = 14 .

y = 1 /5 x − 1                             PARALLEL

7 0
3 years ago
An alloy consists of nickel, zinc, and copper in the ratio 2:7:9.
almond37 [142]
Zinc = 7/18
Divide 4.9 by 7 = 0.7
Multiply by 18 = 12.6

The answer is 12.6 lbs of alloy. Sorry if I'm wrong
6 0
4 years ago
Find the solution of the system of equations. <br>7x -- 8y = -23<br>7x – 7y = -14<br><br>(?,?)​
gtnhenbr [62]

Answer:

(7,9)

Step-by-step explanation:

6 0
3 years ago
The amount of snowfall falling in a certain mountain range is normally distributed with a mean of 90 inches comma and a standard
Debora [2.8K]

Step-by-step answer:

standard deviation (sigma) = 12 inches

mean (mu) = 90 inches.

For 36 years, the standard error of the mean is

e = sigma / sqrt(n) = 12" / sqrt(36) = 2".

Deviation from the mean

= 92.8 -90 = 2.8

Since the standard error of the mean follows the normal distribution, we have

Z=(92.8-90)/2 = 1.4

Looking up the normal distribution tables, or check R, we find

P(Z>1.4) = 1-P(Z<1.4) = 1-0.9192433 = 0.08075666

Answer: P(snowfall>92.8) = 0.0808 (to four decimal places)

3 0
3 years ago
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