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bija089 [108]
3 years ago
11

3/5 of the class were boys. The teacher divided the boys equally into groups so the each group of boys had 1/10 of the number of

students in the class. The teacher then divided the girls equally into groups such that each group of girls had 1/5 of the number of students in the class? How do I do this and what's the answer?
Mathematics
1 answer:
Lana71 [14]3 years ago
4 0
I think boys =18
          girls=12
boys :x
girls:y
student:z
the number of group for the boys :n
the numberof group for the girls :m
so x=(3/5)*z
    y=(2/5)* z
x/y=3/2
3y-2x=0
(1/10)*z*n=(3/5) *z
so n=6
(1/5)*z*m=(2/5)* z
put x=(1/10)*z*6
    y=(1/5)*z*2
 into 3y-2x=0 and z=30
 z=30 so x=(1/10)*30*6=18
               y=(1/5)*30*2=12


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Step-by-step explanation

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Answer:

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Answer:

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(D) AAABCB

Step-by-step explanation:

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A, B, and C = Distinct digits, therefore, A ≠ B ≠ C

The number of digits in the number to be formed = 6 digits

The number of 'A' in the number to be formed = 3

The number of 'B' in the number to be formed = 2

The number of 'C' in the number to be formed = 1

We have;

When A > B > C

The largest possible number = AAABBC

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The largest possible number = CAAABB

When B > A > C

The largest possible number = BBAAAC

When A > C > B

The largest possible number = AAACBB

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