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faust18 [17]
4 years ago
5

Plz help I'm so lost I can't figure out the answer

Mathematics
2 answers:
SIZIF [17.4K]4 years ago
7 0
I would say that for A. It would be 39/8 And for B. It would be 4.875. But I don't know C. Hope this helped
Over [174]4 years ago
7 0
Question 1:
Just multiply 4 by 8, which is 32, then add it to 8 which equals 39.

 So the answer for question one is \frac{39}{8}.

<span>Question 2:
</span>Since 4 is a whole number, you don't have to really worry about it. You will then do 7 ÷ 8, which equals 0.875. That's when you will bring back the 4, which will make your final answer <span>4.875.
</span><span>
Question 3: 
</span>Since \frac{7}{8} is closer to a whole number, just round it to 1, add it to the 4, and you'll get 5. 
<span>
Then take the 5, and multiply it by 4 which = 20. So 20 yd of </span>fabric's enough.

<span>Hope this helped :)</span>
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Answer:

I think the answer is C

Step-by-step explanation:

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3 years ago
4 Jennifer weighs 99 lb. Her weight is
Nady [450]
I’m really sorry. I really try to figure this out but I’m Real bummed out that I can’t even get this. What even is this question? Like tell me the answer if you can even find out ._.
5 0
3 years ago
I NEED HELP PLEASE, THANK YOU!
bixtya [17]

Answer:

\sqrt{37}

Step-by-step explanation:

To find the distance between a point (m, n ) and the line

Ax + By + C = 0

d = \frac{|Am +Bn+C|}{\sqrt{A^2+B^2} }

Here (m, n) = (6, 2) and rearranging the line

6x - y + 3 = 0 ← in general form

with A = 6, B = - 1 and C = 3 , then

d = \frac{|6(6)-1(2)+3|}{\sqrt{6^2+(-1)^2} }

   = \frac{|36-2+3|}{\sqrt{36+1} }

   = \frac{37}{\sqrt{37} }  

Rationalise the denominator by multiplying numerator/ denominator by \sqrt{37}

= \frac{37}{\sqrt{37} } × \frac{\sqrt{37} }{\sqrt{37} }

=\frac{37\sqrt{37} }{37} ← cancel 37 on numerator/ denominator

= \sqrt{37}

5 0
3 years ago
Read 2 more answers
Factor completely, the expression: 2x^3-2x^2-12x
muminat
2x^3-2x^2-12x=2x(x^2-x-6)=(*)\\\\------------------------------\\x^2-x-6\\\\a=1;\ b=-1;\ c=-6\\\\\Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\\sqrt\Delta=\sqrt{25}=5\\\\x_1=\frac{1-5}{2\cdot1}=\frac{-4}{2}=-2;\ x_2=\frac{1+5}{2\cdot1}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)\\\\------------------------------\\\\(*)=2x(x+2)(x-3)
8 0
3 years ago
Please help :) is it linear, if so model the data with and equation.
Yuki888 [10]

Answer:

The relationship is linear: y -5 = 2 (x+7)

Step-by-step explanation:

While the difference between -7 and -5 / -5 and -3 / -3 and -1 is always 2 teh difference between 5 and 9 / 9 and 13 / 13 and 17 is always 4.

y-5 = -1/2 (x +7)

for x= -7 and y = 5 this is true

for x=-5 and y = 9 this is not true

y + 7 = 1/2 (x-5)

for x= -7 and y = 5 this is not true

y -5 = 2 (x+7)

for x= -7 and y = 5 this is true

for x = -5 and y = 9 this is true

for x = -3 and y = 13 this is true

for x = -1 and y = 17 this is true

8 0
4 years ago
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