Question

Given that circle Q has a radius of 5 and a center of (1,4), which point lies on the perimeter of circle Q?

Answer 1

Answer:

(x-1)^2 + (y-4)^2 = 5^2

Step-by-step explanation:

In order to find the points that lie on the perimeter of the circle, you find the  algebraic equation of the circle.

The general equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$         (1)

The last is a circle centered at the point (h,k) and with radius r.

In this case you have a circle with a radius of r = 5, and the circle is centered at (1,4). Then, you have:

h = 1

k = 4

r = 5

You replace the values of h, k and r in the equation (1):

$(x-1)^2+(y-4)^2=5^2$

All point that lies on the curve of the last equation, are point that lie on the perimeter of the circle