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Natasha_Volkova [10]
3 years ago
13

In a class test, keith, ethan, and hannah score 6, 4, and 8 respectively. the mean of these scores is 6. therefore, the standard

deviation of their scores is:
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
5 0
<span>To find StDev, we first have to find the mean of the squared differences. The differences between each score and the mean are 0,-2,2, respectively, giving squared values of 0,4,4. To find the variance, we take the sum of the three values and divide it by the number of values in the total set (3). This gives 8/3 or 2.6667. To find the population StDev, then, take the square root of the variance (2.6667), to find 1.633.</span>
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Passes through (1,12) and has a vertex (10,-4)
agasfer [191]

Answer: 16/81 (x-10)^2 -4

Step-by-step explanation:

To write a vertex equation with just a point and the vertex, you have to figure out the variables.

In vertex form, the equation is y = a (x-h)^2 + k

Your y is 12, x = 1, h = 10, and k = -4

Plug everything into equation

12 = a (1 - 10)^2 -4

12 = a (-9)^2 - 4

12 = 81a - 4

16 = 81a

16/81 = a

Now you know what the 'a' value is.

If you graph 16/81 (x-10)^2 -4 , you will get a point at (1,12) and a vertex of (10,-4)!

I hope this helps!

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3 years ago
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cestrela7 [59]
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2 years ago
What is the rate of change for the function y= 5x+ 25
charle [14.2K]

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4 0
2 years ago
What is the length of side a? Round to the nearest tenth of an inch. <br><br> Please and thank youuu
lord [1]

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Write the equation of the parabola in vertex form.
stellarik [79]

well, looking at the picture of this vertically opening parabola, it has a vertex at 0,0 and it passes through 2,1 hmm ok

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y = a(x-0)^2+0\qquad \stackrel{\textit{we also know that}}{x=2\qquad y = 1}\qquad \implies 1=a(2-0)^2+0 \\\\\\ 1=4a\implies \cfrac{1}{4}=a~\hspace{10em} \boxed{y=\cfrac{1}{4}x^2}

8 0
2 years ago
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