The two quadrilaterals are given similar .
In any similar figure sides are in proportion.The second largest side of quadrilateral ABCD is 16 ft .Let the second longest side of quadrilateral EFGH be x ft. These sides will be in proportion to each other .
The second shortest side of quadrilateral EFGH that is GF will be proportional to the third longest side of quadrilateral ABCD that is BC
We can form a proportion with the proportional sides:
To solve for x we cross multiply
12x=(16)(18)
12x=288
Dividing both sides by 12 we get
x=24.
The second longest side of quadrilateral EFGH is 24 ft.
I think you should add 5x
4x-x-7x just combine all like terms 4x-x=3x rewrite 3x-7x= -4x. 4x-x-7x=-4x
Hope this helps have a nice day
Speed of Jordan while driving from his home = 56 mph
After Jordan travels 2 miles then Roman started from his house.
Speed of Roman while driving after leaving home= 60 mph
Let after t hours they meet.
And let they cover the distance =d i.e point at which meet.
After time t distance covered by Jordan= 56 t +2
Roman has to cover the distance to catch Jordan= 60 t
A.T.Q
⇒ 60 t=56 t + 2
⇒4 t=2
⇒t=1/2
So, when d = 56×1/2+2=28+2=30 miles
Roman will catch Jordan.
From the above four solutions ,( C.) d = 56 t ,d = 60 t – 2 , Satisfies the above criteria.
So C is the correct answer.
Answer:
Answers 2,3, and 4 are all biased.
Step-by-step explanation:
She has to check ALL her patients to be unbiased. Otherwise she is showing favoritism and bias.