We are given the equations 3x+5y=-3 and x-5y=-5.
Both equations have a 5y term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.
3x + 5y = -3
+x - 5y = -5
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4x + 0y = -8
The y terms cancel out since one is positive and one is negative. Now we can solve for x.
4x = -8

x = -2
Now plug -2 in for x in one of the original equations to find y.
(-2) - 5y = -5
-5y = -3
y = 3/5
Our answer as an ordered pair is (2, 3/5)
Answer:
shape AREA= 35cm^2
Step-by-step explanation:
you should know that this shape is a combination of triangle and trapezoid. therefore you have to find the area of each shape and add them.
A=h/2(b1 + b2) for trapezoid
A=2/2((4+4)+4)
A=1*12
A=12cm^2
A=bh/2. for TRIANGLE
A=1/2((4+4)*5.75)
A=1/2(46)
A=23cm^2
shape AREA= triangle AREA + trapezoid AREA
shape AREA=12cm^2 + 23cm^2
shape AREA= 35cm^2
Answer:
The area of the pentagon is approximately 21 square units
Step-by-step explanation:
The radius of the circle in which the regular pentagon is inscribed, r = 3
The area of a pentagon, 'A', inscribed in a circle with radius, r is given as follows;
A = 5×(1/2) ×2×r·sin(32°)×r·cos(32°) = (5/2)×r²×sin(72°)
Therefore, the area of the pentagon, A = (5/2)×3²×sin(72°) ≈ 21.3987716166 ≈ 21
The area of the pentagon, A ≈ 21 square units.
Answer:
BOC= 110 degrees
Step-by-step explanation:
you can refer the above explanation