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4 years ago

Y varies inversely with the square of x and y=2 when x=6. Find y when x=2.

Mathematics

1 answer:

Olin [163]4 years ago

5 0

Y=6 because they are inverse of each other so opposite or flipped

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3 years ago

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Which line is parallel to line r? line p line q line s line t

pychu [463]

Answer:

Line S

Step-by-step explanation:

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3 years ago

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2. Tyson multiplies 75 by 1.15. Which number might Tyson be trying to find? |A 115%of 75||| B 15% of 75||| C 11.5% of 75||| D 1.

Yanka [14]

Answer:

115% of 75 is equivalent to 75 by 1.15 = 8.625 , This two are equivalent

Step-by-step explanation:

Given as :

Tyson multiplies 75 by 1.15

I .e 75 × 1.15 = 86.25

Now A ) 115% of 75 = $\frac{115}{100}$ × 75 = 86.25

B) 15% of 75 = $\frac{15}{100}$ × 75 = 11.25

C) 11.5% of 75 = $\frac{11.5}{100}$ × 75 = 8.625

D) 1.15% of 75 = $\frac{1.15}{100}$ × 75 = 0.8625

∵ 115% of 75 is equivalent to 75 by 1.15 , so Tyson try to find the option A

Answer

7 0

4 years ago

If cosθ=2/3 find cscθ using identities. This is in quad. 1.

laiz [17]

Step-by-step explanation:

cos θ = 2/3

$\quad \twoheadrightarrow\sf {cos \; \theta = \dfrac{Base}{Hypotenuse} } \\$

Hence, base = 2 units and hypotenuse = 3 units.

$\quad \twoheadrightarrow\sf { H^2 = B^2 + P^2} \\$

$\quad \twoheadrightarrow\sf { P^2 = H^2 - B^2} \\$

$\quad \twoheadrightarrow\sf { P^2 = (3)^2 - (2)^2} \\$

$\quad \twoheadrightarrow\sf { P^2 = 9- 4} \\$

$\quad \twoheadrightarrow\bf { P = \sqrt{5}} \\$

Now, we know that :

$\quad \twoheadrightarrow\sf {cosec \; \theta = \dfrac{Hypotenuse}{Perpendicular} } \\$

$\quad \twoheadrightarrow\bf{cosec \; \theta = \dfrac{3}{\sqrt{5}} } \\$

Therefore, the required answer is 3/√5.

4 0

2 years ago

Gravity Hospital purchased a new item of equipment on January 1,20X1. The equipment has an estimated useful life of ten years an

qaws [65]

Answer:

$25000

Step-by-step explanation:

If the salvage value is 20% of the cost, then 80% of the cost will be depreciated over 10 years. Over the 5 years from Jan 1 20X1 to Dec 31 20X5, the $10,000 accumulated depreciation represents 5/10 of that 80%, or 40% of the initial cost.

$10,000 = 0.40 × cost

$10,000/0.40 = cost = $25,000

The acquisition cost of the equipment was $25,000.

8 0

3 years ago