A base substitution of G:C to A:T after two rounds of replication.
Kinetic energy = 0.5*M*V^2
Q7-
0.5*3*(2^2)= 6J
Q8a-
0.5*2*(2^2)= 4J
0.5*4*(3^2)=18J
the second ball has more kinetic energy.
Q8b-
at the max height, all the kinetic energy is converted to potential energy,
gravitational potential energy is = M*g*h
that theory would apply if you wanted to work out the maximum height achieved if the balls were thrown upward by rearranging. But, we are simply working out which ball will have more potential energy so:
First ball:
2kg*9.81(g)*10m = 196.2J
Second ball
4kg*9.81*10m= 392.4J
The second ball has more potential energy
The exposure of certain types of radiation
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Answer: hydrolysis of intermediate palmitoyl Co A ,with loss of labeled CoA.before reaching the matrix gives the answer
Explanation:
This is because when the labeled Coenzyme A of the Plamitate combines as Palmitoy-CoA with oxaloacetate to form intermediate (palmitoyl-CoA )in Citric Acid cycle:
CoA is hydrolysed with loss of the labelled CoA which returns to the cystosol. Therefore, the labelled CoA does not reach the matrix of the mitochondrial,but returns to the Cystosol.
Consequently, the CoA in the Cystosol will be labelled in palmitoylCoA and the one in the matrix of the liver mitochondrial will be non radioactive(,will not labelled).
