The MRI shows every slice of the brain, a CT shows circulation, possibly the outside of the brain.
What did one cell say to his sister cell that stepped on his toe?
Mitosis!
Answer:
50% wild type and 50% black i.e. 1:1 phenotypic ratio
Explanation:
Given, b+ = wild type allele
b = recessive allele
b+b+ = dominant wild type
b+b = heterozygous wild type
bb = recessive black
First cross: female b+b (wild type) X male bb (black) = bb, bb, b+b, b+b
Since bb and b+b are in 1:1 phenotypic ratio, 52 black and 58 wild type progeny are produced.
From this progeny second cross occurs between:
female bb (black) X male (wild type) b+b = bb, bb, b+b, b+b
Again the same 1:1 phenotypic ratio is obtained. Half of the progeny will be be black (bb), other half will be wild type (b+b).
Answer: Option A.
Transverse tubules rapidly move the action potential to the interior of the muscle potential.
Explanation:
Transverse tubules are cylindrical pockets found in the plasma membrane of muscle cells. They are formed from phospholipid bilayer or sarcolemma of skeletal or cardiac muscle cells. They have membrane that have large concentration of ion channels,transporters and pump. They permit action potention into the cell and also to a particular structure sarcuplasmic reticulum. They play a role in regulating cellular calcium concentration.
