The speed of the ball 0.60 seconds after it is released is 6.8 m/s.
Newton's law of motion is given by:
v = u + gt
where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity and t is the time.
Given that:
u = 0.8 m/s, g = 10 m/s², t = 0.6s. Hence:
v = 0.8 + 10(0.6)
v = 6.8 m/s
Therefore the speed of the ball 0.60 seconds after it is released is 6.8 m/s.
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In homogeneous mixture the constituent of the mixture are uniform and there is no presence of physical barrier between them.
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