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Nat2105 [25]
3 years ago
13

At an intersection, the red-light times are normally distributed with a mean time of 3 minutes and a standard deviation of 0.25

minutes. Using the empirical rule, approximately what percent of red lights last between 2.5 and 3.5 minutes?

Mathematics
1 answer:
denpristay [2]3 years ago
3 0

Percent of red lights last between 2.5 and 3.5 minutes is 95.44% .

<u>Step-by-step explanation:</u>

Step 1: Sketch the curve.

The probability that 2.5<X<3.5 is equal to the blue area under the curve.

Step 2:

Since μ=3 and σ=0.25 we have:

P ( 2.5 < X < 3.5 ) =P ( 2.5−3 <  X−μ < 3.5−3 )

⇒ P ( (2.5−3)/0.25 < (X−μ)/σ < (3.5−3)/0.25)

Since, Z = (x−μ)/σ , (2.5−3)/0.25 = −2 and (3.5−3)/0.25 = 2 we have:

P ( 2.5<X<3.5 )=P ( −2<Z<2 )

Step 3: Use the standard normal table to conclude that:

P ( −2<Z<2 )=0.9544

Percent of red lights last between 2.5 and 3.5 minutes is 0.9544(100) = 95.44% .

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Whats greater .12 or 12/16​
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Given: PSTR is a parallelogram m∠T:m∠R=1:3, RD ⊥ PS , RM ⊥ ST Find: m∠DRM
balu736 [363]

Answer:

m∠DRM = 45°

Step-by-step explanation:

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∵ m∠T : m∠R = 1 : 3

∴ m∠R = 3 m∠T ⇒ (2)

- Substitute (2) in (1)

∴ m∠T + 3 m∠T = 180

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∴ m∠R = 3 × 45 = 135°

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3 years ago
The length of a rectangle is four more than triple the width. if the perimeter is 120 inches, find the dimensions.
mezya [45]
120/2=60 (sum of both lengths)
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length=46
width=14
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