What number of tickets would result in the same proce for each student under either proposal?

Laws of indices please solve

lorasvet [3.4K]

Answer:

here ,

$\sqrt[3]{x {}^{3} y {}^{3} }$

$= (x {}^{3} y {}^{3} ) {}^{ \frac{1}{3} }$

therefore the anwer is xy.

was it hellful plz let me know..

5 0

3 years ago

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If 2x• 3x +(2•3 )x +6x= 648, find x.

klasskru [66]

Answer:

x = -1 ± √109

Step-by-step explanation:

2x • 3x + (2 • 3)x + 6x = 648

According to PEMDAS (parentheses/exponents | multiplication/division | addition/subtraction), we should solve the parentheses first.

(2 • 3) = 6

Now we have:

2x • 3x + (6)x + 6x = 648

Now let's multiply.

2x • 3x = 6x²

6 • x = 6x

Now we have.

6x² + 6x + 6x = 648

Combine like terms.

6x² + 12x = 648

Let's factor out a 6.

6(x² + 2x) = 648

Divide both sides by 6.

x² + 2x = 108

Let's use completing the square.

Our equation is in a² + bx = c form.

Divide b by 2.

2/2 = 1

Then square it.

1² = 1

Add 1 to both sides.

x² + 2x + 1 = 108 + 1

Simplify.

x² + 2x + 1 = 109

Now we want to factor the left side. A shortcut is just to use b/2.

(x + 1)² = 109

Take the square root of both sides.

x + 1 = ±√109

The square root is as simplified as possible.

Subtract 1 from both sides.

x = -1 ± √109

Hope this helps!

4 0

3 years ago

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A pair of fair dice is cast. what is the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one

WITCHER [35]

If a pair of fair dice is cast, the probability that the sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is given by:

$\frac{P(sum\, of\, 9\, \cup\,3)}{P(3)}$

The number of outcomes of sum of 9 where at last one is 3 is (3, 6) and (6, 3) = 2.

The number of outcomes of last one of the numbers falling uppermost is a 3 is (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (1, 3), (2, 3), (4, 3), (5, 3) and (6, 3) = 11.

Therefore, the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is 2 / 11.

5 0

4 years ago

50 PONTIS Score for Question 3: ___ of 5 points) 3. Solve the given inequality and graph the solution on a number line. Show you

nadya68 [22]

Answer:

If x equals -1 or anything less than -1, then the inequality statement is false

Step-by-step explanation:

So to find the number x has to be for the statement to be false, we have to find what number x would be to make it so both sides equal the same thing. So in this case, it would be -1 because 5-3 equals 2 and -2x=2 only if x=-1. So anything greater than -1 would make the statement true.

I hope this helped.

5 0

3 years ago

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How do I write 0.632 in two different forms

s2008m [1.1K]

six hundred thirty-two thosuandths and .6 +.03 + .002

7 0

3 years ago

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