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Serjik [45]
3 years ago
6

Given the literal equation ab/a+b = c , with b = –1 + a, what is the value of c if a = 5?

Mathematics
2 answers:
Elan Coil [88]3 years ago
6 0

Answer:

Option A

Step-by-step explanation:

The given literal equation is \frac{ab}{a+b}=c

with b = ( a-1 )

We have to calculate the value of c when a = 5  

Now we put b = ( a - 1 ) in literal equation

\frac{a(a-1)}{a+(a-1)}=c

c=[\frac{a(a-1)}{2a-1}]

Now we have to calculate the value of c when a = 5

c=\frac{5(5-1)}{(2*5)-1}

\frac{5\times 4}{10-1}

=\frac{20}{9}

Option A is the answer.

Nesterboy [21]3 years ago
3 0

The solution would be like this for this specific problem:

ab/a+b = c 

b = -1 + a

for c:
<span>(5(-1 + 5))/(5 + (-1 +5))
</span><span>5(4)/ 5 + 4
</span><span>20 / 9
</span>

<span>The correct answer between all the choices given is the first choice or letter A. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>



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