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2 years ago

6

The slope of a line is –4 and its y-intercept is (0, 4). What is the equation of the line that is perpendicular to the first lin

e and passes through (–8, 2)?

1 answer:

azamat2 years ago

4 0

The first equation is y = -4x + 4

so I think, you make the slope positive.

y = 4x + c

2= 4(-8) + c
2 = -32 + c
34 = c

y = 4x + 34

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Answer:

The cost of soft pretzel is $1.25

Step-by-step explanation:

Let $x be the price of one slice of pizza and $y be the price of one soft pretzel.

1. 9 slices of pizza cost $9x and 5 soft pretzels cost $5y. Together they cost $33.25, then

9x+5y=33.25.

2. 4 slices of pizza cost $4x and 6 soft pretzels cost $6y. Together they cost $19.50, then

4x+6y=19.50.

3. Solve the system of two equations:

$\left\{\begin{array}{l}9x+5y=33.25\\4x+6y=19.50\end{array}\right..$

Multiplythe first equation by 4, the second equation by 9 and subtract them:

$4(9x+5y)-9(4x+6y)=4\cdot 33.25-9\cdot 19.50,\\ \\36x+20y-35x-54y=133-175.5,\\ \\-34y=-42.5,\\ \\y=\$1.25.$

Then

$4x+6\cdot 1.25=19.50,\\ \\4x=19.50-7.50,\\ \\4x=12,\\ \\x=\$3.$

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Answer:

Part 1) The equation in slope intercept form is $y=4x-8$

Step-by-step explanation:

Part 1) Write an equation in slope-intercept form for a line that passes through (3,4) (and has a y intercept of -8)

we know that

The equation of a line in slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$b=-8$

$point\ (3,4)$

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$4=m(3)-8$

solve for m

$4+8=3m$

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