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liq [111]
3 years ago
14

The manager suggests that Darryl should purchase the deli’s bread from Store D because they sell the most loaves of bread for th

e best price. Is this true? Why or why not? Explain your reasoning.
Mathematics
2 answers:
mina [271]3 years ago
6 0
<span>No, store D does not have the best deal when you compare the unit prices. The best deal isn’t from having more loaves. The best deal is from store B because the unit price is the lowest.</span>
Dmitry [639]3 years ago
4 0

Answer:

No, this is not the best deal.

The unit price at Store D is higher than the unit price at Store B.

The most loaves is not always the best deal.

Darryl should purchase bread from Store B.

Step-by-step explanation:

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If FE = 12 and DE = 5, find DF.
Anton [14]
If fe =12 and. De= 5 df would be 17
4 0
4 years ago
Durable press" cotton fabrics are treated to improve their recovery from wrinkles after washing. "Wrinkle recovery angle" measur
xenn [34]

Answer:

t=\frac{134.36-135.25}{\sqrt{\frac{15.71^2}{11}+\frac{6.23^2}{8}}}=-0.17  

p_v =P(t_{(17)}

So the p value is a very high value and using any significance level for example \alpha=0,1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis and we have enough evidence to support the claim.  Since the mean for Hylite is not significantly less than the mean for Permafresh.

Step-by-step explanation:

1) Data given and notation

Hylite:[140,139, 138 , 117, 141, 102, 127, 137, 164, 142, 131]

Permafresh:[124,144,136,133,139,132,141,133]

\bar X_{Hylite} represent the mean for the sample Hylite

\bar X_{permafresh} represent the mean for the sample LPermafresh

s_{Hylite} represent the sample standard deviation for the sample Stick

s_{Permafresh} represent the sample standard deviation for the sample Liquid

n_{Hylite}=11 sample size for the group Hylite

n_{Permafresh}=8 sample size for the group Permafresh

t would represent the statistic (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Hylite is better for Hylie:

H0:\mu_{Hylite} \geq \mu_{Permafresh}

H1:\mu_{Hylite} < \mu_{Permafresh}

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{Hylite}-\bar X_{Perm}}{\sqrt{\frac{s^2_{Hylite}}{n_{Hylite}}+\frac{s^2_{Perm.}}{n_{LPerm.}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

In order to calculate the mean and the sample deviation we can use the following formulas:

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

3) Calculate the statistic

First we need to calculate the mean and deviation for each sample, after apply the formulas (2) and (3) we got the following results:

\bar X_{Hylite}=134.36 s_{Hylite}=15.71

\bar X_{Permafresh}=135.25 s_{Permafresh}=6.23

And with this we can replace in formula (1) like this:

t=\frac{134.36-135.25}{\sqrt{\frac{15.71^2}{11}+\frac{6.23^2}{8}}}=-0.17  

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:

df=n_{Hylite}+n_{Perm}-2=11+8-2=17

Since is a left tailed test the p value would be:

p_v =P(t_{(17)}

So the p value is a very high value and using any significance level for example \alpha=0,1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis and we have enough evidence to support the claim.  Since the mean for Hylite is not significantly less than the mean for Permafresh.

4 0
3 years ago
2/5 in Fraction form?
hram777 [196]

Answer:

2/5 is fraction form.

0.4 is decimal form btw.

5 0
3 years ago
His composite shape is a rectangle with a semicircle attached on one end. The diameter of the semicircle is 6 feet.
Vera_Pavlovna [14]
We can solve by figuring the area of the rectangle then add it to the area of the semicircle.

Area of the rectangle: length · width = 6 · 10 = 60 ft²

Area of the semicircle: (πd²)/8 = (3.14 · 6²)/8 = (3.14 · 36)/8 = 14.13 ft²

Total area of the figure: 60 + 14.13 = 74.13 ft² ≈ 74 ft²
4 0
3 years ago
Read 2 more answers
Please help due two days ago helpp me please Which measure of center is the most appropriate for the data in Table 1 (Height) in
Stells [14]

Answer:

I think the correct answer is....... The measure of center for table 1 is 61, 62, 58, and 57 inches. The most kids had the same number of inches in this category.

I'm not 100% sure so try at your own risk

Have a great day!

3 0
3 years ago
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