Answer:
()
Step-by-step explanation:
Use nCr to figure this out, plug in the numbers and probabilities and solve
Answer:
20x - 8
Step-by-step explanation:
using the distributive property to simplify (5x-2)4, you would multiply the outside term (4) by each inside term (5x-2).
for example:
4 × 5x = 20x
4 × -2 = -8
once you distribute the 4 into 5x-2, you are left with 20x - 8 which needs no further simplifying
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way
Step-by-step explanation:
- From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
- A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace.
P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
- WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?
P(AA) = (4/52)(3/51) = 1/221.
- WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?
P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.
- WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52.
- The probability of drawing the second queen is also 4/52 and the third is 4/52.
- We multiply these three individual probabilities together to get P(QQQ) =
- P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
- Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
Ok if the number behind the decimal is 4-0... round down, But if the number is 5-9 round up.
Example:65.85
The number behind the decimal is a 8.. So round this number up to the next availible whole number, which is 66.
Answer:
33, 9
Step-by-step explanation:
I33-21I=12
I9-21I=
I-12I=12
Every SUM of an absolute value will always be positive!!
