4 years ago

Simplify. Square root of 121m^8n^4 A. 11mn B. 11m^2n^2 C. 11m^4n^2

Mathematics

1 answer:

Bezzdna [24]4 years ago

5 0

$\sqrt{121m^8n^4}= \sqrt{121} \sqrt{(m^4)^2} \sqrt{(n^2)^2}=11 m^4n^2$

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