A=226.19 A=2πrh+2πr2=2·π·4·5+2·π·42≈226.19467
Answer:
77.2°
Step-by-step explanation:
Consider the triangle JKR.
∠KJR=108.6 (lies on the same line as ∠RJA, angles on a straight line add up to 180)
All the angles in a triangle add up to 180, so:
∠JKR+∠KJR+∠JRK=180
∠JKR+108.6+32.8=180
∠JKR=38.6=∠RKA
Consider ∠RKA. This angle stands on the same arc as ∠RCA.
Since the angle at centre is twice the angle at circumference, 2(∠RKA) = ∠RCA.
2(∠RKA) = ∠RCA
2(38.6)=∠RCA
∠RCA=77.2°
The number you are looking for is 995
Answer: 1.2
Step-by-step explanation:
Let X denotes the grades on a language midterm at Oak Academy.
As per given ,
X follows normal distribution ( because it has symmetric graph)
Formula for z : 
For X = 70, we have
Hence, the z-score for Ishaan's exam grade = 1.2
