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3 years ago

sum of two numbers is 39. the greater number is 7 more than the smaller number. ( set up an equation )

1 answer:

3 0

Let x be the unknown number

2x +7 = 39

2x+7-7 = 39-7

2x = 32

2x/2 = 32/2

x=16

You use the balance method to solve. First, you cancel the +7 by subtracting the 7 ON BOTH SIDES to balance the equation.. After that, you are left with 2x, where you will need to isolate the x by dividing by 2 ON BOTH SIDES to balance it.

Hope this helps

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3 years ago

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What is the value of 2×[34−5×(3+1)] ?

spayn [35]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{28}}}}}$

Step-by-step explanation:

Use BODMAS rule :

Bracket , Of , Division , Multiplication , Addition , Subtraction

$\sf{2 \times [ 34 - 5 \times (3 + 1) ] }$

Add the numbers : 3 and 1

$\dashrightarrow{ \sf{2 \times [ 34 - 5 \times 4 ] }}$

Multiply the numbers : 5 and 4

$\dashrightarrow{ \sf{2 \times [ 34 - 20 \: ] }}$

Subtract 20 from 34

$\dashrightarrow{ \sf{2 \times 14}}$

Multiply the numbers : 2 and 14

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Hope I helped!

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3 years ago

In a board game, each player must roll a number cube and spin a spinner. The number cube is labeled with the numbers 1 through 6

HACTEHA [7]

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Step-by-step explanation:

Sorry if I am wrong. :) but it should be correct.

4 0

2 years ago

I could use some help!!

12345 [234]

Answer:

Step-by-step explanation:

The interquartile range is obtained using the relation :

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6 0

2 years ago

Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(

Inessa05 [86]

Answer:

$2+i$

Step-by-step explanation:

Given the expression:

$\dfrac{4+\sqrt{16-(4)(5)}}{2}$

To find:

The expression of above complex number in standard form $a+bi$ .

Solution:

First of all, learn the concept of $i$ (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by $i$ .

Value of $i =\sqrt{-1}$ .

Now, let us consider the given expression:

$\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i$

So, the given expression in standard form is $2+i$ .

Let us compare with standard form $a+bi$ so we get $a =2, b =1$ .

$\therefore$ The standard form of

$\dfrac{4+\sqrt{16-(4)(5)}}{2}$

is: $\bold{2+i}$

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2 years ago