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Simora [160]
4 years ago
14

Quick what's 13 x 9!!!​

Mathematics
1 answer:
Law Incorporation [45]4 years ago
6 0
It’s 117 duh...........
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J = d + 7
ivolga24 [154]

Answer:

2

Step-by-step explanation:

correct me if I'm wrong

8 0
3 years ago
Can someone please help me!?!
poizon [28]

Answer:

-25 and -4

Step-by-step explanation:

to solve this, you need to use the sum product pattern. this means you're going to take the x factor, 29x and separate it into it's squares.

(x^2+25x)+(4x+100)

then you take out the common factor in each separated equation

x(x+25)+4(x+25)

you see that the items in the parentheses are the same, this means that this is one of the equations you will use when factoring. the rest of the equation that is left out (the common factors) is the other equation

(x+25)(x+4)

to get the zeroes, you set each equation equal to zero and solve

x+25=0           x+4=0

x= -25             x= -4

3 0
3 years ago
Two X squared Plus three X - two is​
vodka [1.7K]

that's the simplification mod

6 0
3 years ago
Pls answer I will mark brainliest
Lina20 [59]

Answer:

268.08

Step-by-step explanation:

first you take your radius and put it in the equation V=4/3πr³ when you insert the 4 you calculate it to get 268.08257

3 0
2 years ago
Read 2 more answers
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
3 years ago
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