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AURORKA [14]
3 years ago
12

(v) 4x + x + x - 72(vi) 5+2x---​

Mathematics
1 answer:
Strike441 [17]3 years ago
8 0

(2,-6)+(9,9)

(0,8)x(7,-52)

(2,-6)x (9,9)

this is it Simplified

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Use the context of a 24-pack of soda to explain why 3/8 is NOT equivalent to 5/12 . Answer in number of cans.
juin [17]

Answer:

In a 24 pack of soda, 1/8 would be 3 cans (24/8 = 3). 1/12 would be 2 cans (24/12=2).

So 3/8 is 9 cans of soda and 5/12 is 10 cans of soda, so they are not equivalent because the number of soda cans is not the same.

4 0
3 years ago
Please answer please please answer need the answer
Korvikt [17]
A = 1/2 bh
A = 1/2 (21)(8)
A = 1/2 (168)
A = 84
5 0
3 years ago
Rewrite in polar form: x^2+y^2-2y=7
Alchen [17]
X²+y²-2y=7
using the formula that links Cartesian to Polar coordinates
x=rcosθ and y=r sin θ
substituting into our expression we get:
(r cos θ)²+(r sin θ)²-2rsinθ=7
expanding the brackets we obtain:
r²cos²θ+r²sin²θ=7+2rsinθ
r²(cos²θ+sin²θ)=7+2rsinθ
using trigonometric identity:
cos²θ+sin²θ=1
thus
r²=2rsinθ+7
Answer: r²=2rsinθ+7
8 0
3 years ago
Read 2 more answers
Help me please. 30 points :)
Nataly [62]

\frac{(5 \:  -  \: 8x)}{( \sqrt{5 \:  -  \: 8x} )}  \:  =  \:  \sqrt{5 \:  -  \: 8x}
For the result to be Real,
5 \:  -  \: 8x \:  \geqslant  \: 0
8x \:  \leqslant  \: 5
x \:  \leqslant  \:  \frac{5}{8}
( \frac{(5 - 8x)}{( \sqrt{5 - 8x} )} ) \:  \times  \:  (\frac{ \sqrt{5 - 8x} }{ \sqrt{5 - 8x} } ) \:  =  \:  \frac{ {(5 \:  -  \: 8x)}^{ \frac{3}{2} } }{(5 \:  -  \: 8x)}
Hence,
\frac{{(5 \:  -  \: 8x)}^{ \frac{3}{2} } }{(5 \:  -  \: 8x)}
is the required form.

3 0
3 years ago
What are the values of x in this equation?
NNADVOKAT [17]

Answer:

A. x = 0, x = -3, x = 2, and x = -2

Step-by-step explanation:

x^{4} +12x=4x^{2} +3x^{3}

by moving the terms on the left side to the right side

x^{4} -3x^{3} -4x^{2} +12x = 0

factor an x^{3} from x^{4} -3x^{3}

and factor - 4x from -4x^{2} +12x

the equation becomes :

x^{3} (x - 3  )-4x  (x - 3) = 0

take (x - 3)  as  a common factor the equation becomes :

(x-3)(x^{3}-4x  ) = 0

thus

x - 3 = 0⇒x = 3

and

x^{3} - 4x = 0 by factoring an x we get :

x(x^{2}-4 ) =0 ⇒ x = 0 and x^{2} - 4 = 0

x^{2} - 4 =0⇒x = 2 and x = -2

Thus

the values are :

x = 0, x = -3, x = 2, and x = -2

4 0
3 years ago
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