What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
360°-90°(right angle)-90°(right angle)-52°=128°
X=128°
Hope this helps :)
$16.80 because 12*14 equals 168 then you take 14 times 1.20
Answer:
23
Step-by-step explanation:
I don't know j subtract 18 from 41
2.2x+4.4
2.2(x+2) is your answer
