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Ahat [919]
3 years ago
13

A white-tailed deer can sprint at speeds up to 30 miles per hour. American bison can run at speeds up to 3,520 feet per minute.

Which animal is faster and by how many miles per hour? There are 5,280 feet in one mile.
Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0
3520 ft per minute=40 mi per hour, which means the American bison is faster by 10 more miles per hour.
pav-90 [236]3 years ago
4 0

Answer:

10mph bison faster than deer

Step-by-step explanation:

U don't need to know all dat

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Write the first five terms of the sequence defined by the explicit formula
denis-greek [22]

<u>Answer:</u>

The correct answer option is: 19, 13, 3, -11, -29.

<u>Step-by-step explanation:</u>

We are given the following explicit formula for an arithmetic sequence:

a_n=21-2n^2

So to find the first five terms of this sequence, we will substitute the values of n (num here in the given formula:

a_1=21-2(1)^2\\\\a_1=19


a_2=21-2(2)^2\\\\a_2=13


a_3=21-2(3)^2\\\\a_3=3


a_4=21-2(4)^2\\\\a_4=-11


a_5=21-2(5)^2\\\\a_5=-29

Therefore, the first five terms of the sequence defined by the explicit formula a_n=21-2n^2 are 19, 13, 3, -11, -29.


5 0
3 years ago
Read 2 more answers
Mariya is solving the quadratic equation by completing the square.
DerKrebs [107]

Answer:

A=4

Step-by-step explanation:

Mariya was solving:

4x2-20x+3=0  

4x2-20x=-3

A(x2-5x)=-3

At this point, we can know that 4*x2=4x2 and 4*5x=20x, son A=4

7 0
3 years ago
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The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.
VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

\int\limits^2_{-1} {(f(x) - g(x))} \, dx

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx

We know that:

\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}

\int\limits^{}_{} {1} \, dx = x

\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}

Then our integral is:

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2}  + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3}  + (-1) - \frac{(-1)^2}{2}  )

The right side is equal to:

(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6

The bounded area is 5 + 5/6 square units.

3 0
2 years ago
I can’t seem to find the value of n in this peoblem
Annette [7]

Answer:

9

Step-by-step explanation:

you can always use guess-and-check:

124 seems rather high

(6)P(2) = 6!/4! = 6x5 ≠ 72

(9)P(2) = 9!/7! = 9x8 = 72

3 0
3 years ago
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Notebooks cost $ 1.20 each. This weekend they will be on sale for $ 0.80. What percentage is the sale
Rainbow [258]

From the information we have, we know that each book costs 1.20 dollars. So we shall say this price is at 100% .

Now we need to form an equation to get the percentage  when the books are sold at 0.80 dollars.

100% = 1.20

       x = 0. 80

Where x is the new percentage when the sale is at 0.80 dollars.

We cross multiply the equation:

1.20 *x = 0.80 * 100

1.2x = 80

x = 80/1.2

x = 66.7%

Round off 66.7 to the nearest tenth we get 67%

The notebooks are sold at 67% (of the original cost).

6 0
3 years ago
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