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Rasek [7]
3 years ago
5

1.) Identify the domain of the equation y = x2 − 6x + 1.

Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0
1. "All real numbers" is the one domain of the equation y = x2 − 6x + 1 among the following choices given in the question. The correct option among all the options that are given in the question is the fourth option or option "D".

2. "Left by 4 units" is the one among the following choices given in the question that gives the direction and by how many units f(x) be shifted to obtain g(x). The correct option is option "A". 
erastovalidia [21]3 years ago
4 0
<h2>Answer:</h2>

1)

The domain is

          D.) All real numbers

2)

        The correct answer is:

          A.)    Left by 4 units

<h2>Step-by-step explanation:</h2>

Ques 1)

The equation of a parabola is:

          y=x^2-6x+1

The equation is a quadratic equation and we know that the polynomial function is defined for all of the x i.e. for all the real values.

Hence, the domain is:

              All real numbers.

Ques 2)

 Functions f(x) and g(x) are given by:

       f(x)=x^2

and g(x)=x^2+8x+16\\\\i.e.\\\\\\g(x)=(x+4)^2

i.e. the function g(x) could be written as:

          g(x)=f(x+4)

We know that the translation of the original function f(x) to f(x+k) is a shift of the function f(x) k units to the right or left depending whether k is negative or positive respectively.

Here k=4>0

Hence, the shift is 4 units to the left.          

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KatRina [158]

Answer:

65 because 12 plus 9 is 21 then 3 times 21 is 65

4 0
2 years ago
What is two and one-fourth subtracted by one-eighth?
Illusion [34]
Two and one eighth is the answer
3 0
3 years ago
You are arguing over a cell phone while trailing an unmarked police car by 25 m; both your car and the police car are traveling
BARSIC [14]

Answer:

  (a) 15 m

  (b) ground speed: 26.14 m/s (94.1 km/h); relative speed 12 m/s

Step-by-step explanation:

We can choose the frame of reference to be the trailing car. We can start counting time from the point the lead car begins deceleration. Then its position (in meters) relative to the trailing car is ...

  d(t) = 25 - 5/2t² . . . . . . where 25 m is the initial distance and -5 is the acceleration in m/s².

(a) Then the distance between cars at t=2 is ...

  d(2) = 25 - (5/2)·4 = 15 . . . . meters

__

(b) The <em>relative velocity</em> at 2.4 seconds is ...

  d'(t) = -5t

  d'(2.4) = -5(2.4) = -12.0 . . . m/s

The closure speed with the police car is 12 m/s.

__

We need to do a little more work to find the ground speed of the trailing car when the cars bump.

The distance between the cars at t=2.4 seconds is ...

  d(2.4) = 25 -(5/2)2.4² = 10.6 . . . . meters

At the closure speed of 12 m/s, it will take an additional ...

  10.6 m/(12 m/s) = 0.8833... s = 53/60 s

to close the gap. The speed of the trailing car at that point in time will be the original speed less the deceleration for 0.8833 seconds:

  (110 km/h)·(1/3.6 (m/s)/(km/h))-(5 m/s²)(53/60 s)

     = 26 5/36 m/s = 94.1 km/h

_____

<em>Comment on following distance</em>

To avoid collision, the trailing car must be trailing by at least the distance it covers in 2.4 seconds, about 73 1/3 meters.

6 0
3 years ago
How many quarts are there in 4 gallons and 6 pints?
umka21 [38]

4 Gallon is 20 Quarts

6 pints is 3 Quarts

Total = 20+3

=23 Quarts

Therefore 4 Gallons and 6 pints are 23 Quarts

Must click thanks and mark brainliest

3 0
3 years ago
Find the roots of:
Elena-2011 [213]

\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \  2x^3-7x^2+8x-3=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

  | 2  -7    8  -3

<u>1 |      2   -5   3</u>

  | 2   -5    3  0

<u> 1 |      2     -3   </u>

    2   -3     0

So the factorization is (x-1)² (2x-3)=0. So:

                     \bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2}  }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \  x^3-x^2-4=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

      |  1  -1  0  -4

  <u>2  |     2  2     </u>

         1  2  2  0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

                   \bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \  6x^3+7x^2-9x+2=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

   | 6    7       9      2

<u>-2 |      -12    10     -2</u>

     6    -5     1       0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

         \bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}

                     \large\displaystyle\text{$\begin{gathered}\sf  \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}

6 0
2 years ago
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