Consider the given monomials. Let us determine the sum of these monomials,
1. 
= 
Therefore, the sum of the given monomials is
.
2. 
= 
= 
Therefore, the sum of the given monomials is
.
3. 
= 
Therefore, the sum of the given monomials is
.
4. 
= 
= 
Therefore, the sum of the given monomials is
.
Answer:
A-a rectangle with two 12-ft sides and two 2-ft sides
Step-by-step explanation:
Got it right on edge
5x - 2y = -4
To find the x-intercept, you make y = 0
So, our equation now looks like this :
5x - 2(0) = -4
Simplify.
5x - 0 = -4
5x = -4
Divide both sides by 5.
x = -4/5
So, our x-intercept is -4/5
* Remember, ALWAYS make y = 0 when solving for the x-intercept*
~Hope I helped!~
Answer: 12 in. by 10 in.
Step-by-step explanation:
Given: The dimensions of photo is 10 in. by 8 in.
Therefore, Area of photo= 
Area of frame with photo=120 square inches
Let x be the width of the frame, then we have
Length of frame with photo= 10+2x inches
Width of frame with photo =8+2x inches
Now, 
![80+16x+20x+4x^2=120\\\Rightarrow\ 4x^2+36x-40=0\\\Rightarrowx^2+9x-10=0\\\(x-1)(x+10)=0\\\Rightarrow\ x=1,...........[text{Since length can not be negative so it cannot be -10}]](https://tex.z-dn.net/?f=80%2B16x%2B20x%2B4x%5E2%3D120%5C%5C%5CRightarrow%5C%204x%5E2%2B36x-40%3D0%5C%5C%5CRightarrowx%5E2%2B9x-10%3D0%5C%5C%5C%28x-1%29%28x%2B10%29%3D0%5C%5C%5CRightarrow%5C%20x%3D1%2C...........%5Btext%7BSince%20length%20can%20not%20be%20negative%20so%20it%20cannot%20be%20-10%7D%5D)
Thus, dimension of frame = 
Answer:
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Step-by-step explanation:
