Hi there!
Let th' two number be ' a ' and ' b ' [ a > b ]
According to th' question :-
→ The largest of two numbers is 12 more than the smaller number.
a = 12 + b ---(i)
→ Sum of the two numbers is 74.
a + b = 74
b = 74 - a ---(ii)
Substitute th' value of ' b in Eqn. :-
a = 12 + (74 - a)
a = 86 - a
a + a = 86
2a = 86
a =

= 43
Now,
Substitute th' value of ' a ' in Eqn. (ii)
b = 74 - b
b = 74 - 43
b = 31
Hence,
The required answer is :-
• The smaller number is 31
• The largest number is 43
~ Hope it helps!
Answer:
The value is
Step-by-step explanation:
From the question we are told that
The probability of the device failing during the warranty period is 
The sample size is 
The random variable considered is x = 15
Generally this is distribution is binomial given the fact that there is only two out comes hence
X which is a variable representing a randomly selected selected electronic follows a binomial distribution i.e

Now the mean is mathematically evaluated as

=> 
=> 
The standard deviation is mathematically represented as

=> 
=> 
Now given that n is very large, then it mean that we can successfully apply normal approximation on this binomial distribution
So
Now applying Continuity Correction we have

Generally 

From the z-table

Thus
Answer: Its a little blurry I cant se
Step-by-step explanation:
Answer:
<em>Given </em><em>x </em><em>=</em><em> </em><em>4</em><em> </em><em>and </em><em>y </em><em>=</em><em> </em><em>3</em>
Step-by-step explanation:
5x +2y -6 = <em>5</em><em>*</em><em>4</em><em> </em><em>+</em><em> </em><em>2</em><em>*</em><em>3</em><em> </em><em>-</em><em>6</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em><em>+</em><em> </em><em>6</em><em> </em><em>-</em><em> </em><em>6</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>2</em><em>0</em>
(f+g)(x) = f(x) + g(x) = x + 11 + 3x^2
(f+g)(5) = f(5) + g(5) = 5 + 11 +3(5^2) = 91