Y=2
Since the table (y) increase by 2 each time the answer would be y=2
Answer:
57 miles
Step-by-step explanation:
342 divided by 5 equals 57 miles
<h3>
Answer: 426 square feet</h3>
Work Shown:
A = area of the rectangle
A = length*width
A = 26*15
A = 390 square feet
B = area of the triangle
B = base*height/2
B = 8*9/2
B = 72/2
B = 36 square feet
C = total area
C = A+B
C = 390+36
C = 426 square feet
Answer:
we have (a,b,c)=(4,-2,0) and R=4 (radius)
Step-by-step explanation:
since
x²+y²+z²−8x+4y=−4
we have to complete the squares to finish with a equation of the form
(x-a)²+(y-b)²+(z-c)²=R²
that is the equation of a sphere of radius R and centre in (a,b,c)
thus
x²+y²+z²−8x+4y=−4
x²+y²+z²−8x+4y +4 = 0
x²+y²+z²−8x+4y +4 +16-16 =0
(x²−8x + 16) + (y² + 4y + 4 ) + (z²) -16 = 0
(x-4)² + (y+2)² + z² = 16
(x-4)² + (y-(-2))² + (z-0)² = 4²
thus we have a=4 , b= -2 , c= 0 and R=4
The events are independent. By definition, it means that knowledge about one event does not help you predict the second, and this is the case: even if you knew that you rolled an even number on the first cube, would you be more or less confident about rolling a six on the second? No.
An example in which two events about rolling cubes are dependent could be something like:
Event A: You roll the first cube
Event B: The second cube returns a higher number than the first one.
In this case, knowledge on event A does change you view on event B (and vice versa): if you know that you rolled a 6 on the first cube you don't want to bet on event B, while if you know that you rolled a 1 on the first cube, you're certain that event B will happen.
Conversely, if you know that event B has happened, you are more likely to think that the first cube rolled a small number, and vice versa.
