The period of f(x)=cos (2pi/3)x is ...?

1 answer:

5 0

Well lets see. if you're being specific about the rigor, then the period means that <span>cos(2Π÷3(x+α))=cos(2Π÷3(x))</span>Therefore this gives <span>2π÷3α=2π</span>so α = 3.
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Gnesinka [82]

Answer:

WXYZ can not be a rectangle because consecutive sides are not perpendicular to each other.

Step-by-step explanation:

The given vertices are W(-4,3), X(1,5), Y(3,1) and Z(-2,-1).

Plot these points on coordinate plane and draw the quadrilateral as shown below.

$Slope=\dfrac{y_2-y_1}{x_2-x_1}$

Using this formula, we get

$m_{WX}=\dfrac{5-3}{1-(-4)}=\dfrac{2}{5}$

$m_{XY}=\dfrac{1-5}{3-1}=\dfrac{-4}{2}=-2$

Now,

$m_{WX}\times =\dfrac{2}{5}\times (-2)=-\dfrac{4}{5}\neq -1$

Here, WX and XY are two consecutive sides of quadrilateral but the product of their slopes is not equal to -1. It means they are not perpendicular to each other.

Since, all interior angles of a rectangle are right angles, therefore, WXYZ can not be a rectangle.