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Maksim231197 [3]
4 years ago
14

What is the solution of the system? Use elimination.

Mathematics
2 answers:
Schach [20]4 years ago
6 0
(one way is to subsitute since both equal 9 you do 3x-4y=-3x+2y then add 3x to both sides 6x-4y=2y add 4y to both sides 6x=6y divide by 6 x=y now subsitute 3x-4x=9 -x=9 multiply -1  x=9  x=y y=-9)


use elimination
add them together to cancel x terms
3x-4y=9
<u>-3x+2y=9  +
</u>0x-2y=18
-2y=18
divide by 2
-y=9
multiply -1
y=-9
subsituete

3x-4y=9
3x-(4 times -9)=9
3x-(-36)=9
3x+36=9
subtract 36 from both sides
3x=-27
divide both sides by 3
x=-9

x=-9
y=-9

the answer is  in (x,y) form
(-9,-9)
the answer is none of them (D is closest)
<u />
Arada [10]4 years ago
6 0

<u><em>Answer:</em></u>

(-9,-9)


<u><em>Explanation:</em></u>

<u>The two given equations are:</u>

3x - 4y = 9

-3x + 2y = 9


<u>First step is to add the two equations in order to eliminate the x.</u>

This will give us:

-4y + 2y = 9 + 9

-2y = 18

y = -9


<u>Now, we substitute with the value of y in any of the equations to get x as follows:</u>

3x - 4y = 9

3x - 4(-9) = 9

3x + 36 = 9

3x = -27

x = -9


Hope this helps :)



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