Question

Did I get this one right

Answer 1

Answer:

Your answer of option b is right.

Step-by-step explanation:

Given that a sinesoidal function has maximum 12 and minimum -6

Hence centre line would be average of these two.

Centre line is $y=\frac{12-6}{2} =3$

i.e. f(x) = a sin (bx+c)+3

Since amplitude = 12-3 =9 we have a = 9

i.e. f(x) = 9 sin (bx+c)+3

Frequency is given as 3, period = 1/3

This gives b = 6pi

f(0) = y intercept =

9sin(c)+3 =3

This gives c=0

Hence correct equation is

$y =9sin 6 \pi x+3$