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Ilia_Sergeevich [38]
3 years ago
14

Match each function with its correct description. Tiles f(x) = (-x + 1)3(x + 2)2(x − 3) f(x) = (-2x + 1)2(x − 3)2(x + 1) f(x) =

(x + 6)(2x − 3)(x − 1)2 f(x) = (x − 2)2(-2x − 1)2(-x + 1) Pairs The degree of the function is 4, and the leading coefficient is positive. arrowBoth The degree of the function is 5, and the leading coefficient is negative. arrowBoth The degree of the function is 6, and the leading coefficient is negative. arrowBoth The degree of the function is 5, and the leading coefficient is positive. arrowBoth
Mathematics
1 answer:
miv72 [106K]3 years ago
8 0
Pairs The degree of the function is 4, and the leading coefficient is positive. arrowBoth 
 f(x) = (x + 6)(2x − 3)(x − 1)2 


 The degree of the function is 5, and the leading coefficient is positive. arrowBoth:
 f(x) = (x − 2)2(-2x − 1)2(-x + 1) 

 The degree of the function is 5, and the leading coefficient is negative. arrowBoth:
 f(x) = (-2x + 1)2(x − 3)2(x + 1) 

 The degree of the function is 6, and the leading coefficient is negative. arrowBoth:
 f(x) = (-x + 1)3(x + 2)2(x − 3) 

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Mars2501 [29]
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3 years ago
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pantera1 [17]
D

explanation:

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4 0
3 years ago
Which of the following represents the distance between the y-intercept and x-intercept of the line whose equation is y = 3x + 12
Arturiano [62]

Answer:

√160

Step-by-step explanation:

For y-intercept, we use y = mx + c. Comparing both, y = mx +c & y = 3x + 12

y intercept = c = 12

Point is (0, 12)

For x intercept, we use y = m(x - d). We have

y = 3x + 12 → y = 3(x - (-4))

Compare both, x intercept = d = - 4

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Using distance formula,

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8 0
3 years ago
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olga_2 [115]

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7 0
4 years ago
In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee
kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that x^{2} =pz

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and  Δ ADB in the attached file , ∠A is common in both triangles

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Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

\frac{x}{z}= \frac{p}{x}

Cross multiply

x^{2}=pz

Hence proved.


7 0
4 years ago
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