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3 years ago

9

Which of the following statements is true about 63 and 20?

2 answers:

guajiro [1.7K]3 years ago

6 0

I hope this helps you

Delvig [45]3 years ago

4 0

The best and most correct answer among the choices provided by your question is the second choice or letter B " <span>They have more than one common factor."</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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Please help me on this question

Delicious77 [7]

Answer:

√20

Or

2√5

Step-by-step explanation:

It is very easy just substitute

It will be:

3 0

3 years ago

Tiffany wants to make 6 batches of cookies. She will need 2 cups of sugar for each

Readme [11.4K]

Answer:12 cups of sugar

Step-by-step explanation:

There is 6 batches each batch has two cups you would do 6x2 for 12 cups.

7 0

3 years ago

What is the common ratio of 5,10,20,40...

Ratling [72]

The common ratio is the multiplication of 2 each time. 5x2= 10// 10x2=20// 20x2=40

5 0

3 years ago

Read 2 more answers

What is value of the X? And what is the value of the missing angle? Pls help

sasho [114]

So it work like this
180-72= 108
x+4=108
x=108-4
x=104

7 0

3 years ago

Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti

hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$

but we will find sample size "n"

$\sqrt{n} = \frac{z_{a} S.D}{maximum error}$

Squaring on both sides , we get

$n = (\frac{z_{a} S.D}{maximum error})^2$

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

$n = (\frac{z_{a} p(1-p)}{maximum error})^2$

n≤ $(\frac{2.56X\frac{1}{2} }{0.02}) ^{2}$ ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is n = 4225

<u>verification</u>:-

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$ = $\frac{2.56 1/2}{\ \sqrt{4225} }$ = 0.0196

substitute all values and simplify we get maximum error is 0.02

4 0

3 years ago