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enot [183]
3 years ago
11

An earthworm has a complete digestive system. How does the earthworm remove undigested food?

Biology
1 answer:
tatiyna3 years ago
4 0
An earthworm removes undigested food by either throwing it up, or getting rid of it from the other end. Hope I helped! ;-)

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What is the superior, broad border of the heart called?.
Tamiku [17]

Answer:

Left ventricle

Explanation:

I think the left ventricle is propably superior and broad border of the simply because it pumps blood and other usefull products from the heart to furthest parts of the body

7 0
2 years ago
In a hypothetical population of 2500 people, 2275 people have brown eyes and 225 people have blue eyes (the homozygous-recessive
aev [14]

Answer:

In the next generation of 4000 children, 1680 of them will be heterozygous for the eye colour.

Explanation:

There's a population of 2500, 2275 of with have brown eyes and 225 blue eyes. <u>Let's call the dominant allele associated with brown colour "B" and the recessive allele associated with blue colour "b"</u>. So the possible genotypes are BB, Bb and bb, being BB and Bb brown eyed individuals and bb blue eyed individuals.

If the population it's in Hardy-Weinberg equilibrium, it means genotypic and allelic frequencies don't change from one generation to the following.

From the information given, we can calculate both allelic and genotypic frequencies.

First, we know that the frequency of the genotype bb it's the amount of blue eyed individuals over the total population.

  • f(bb)=225/2500=0.09

Additionally we know the allelic frequencies can be related to the genotypic ones when the population it's in Hardy-Weinberg equilibrium. Particularly we can say:

  • f(bb)=[f(b)]^2 => f(b)=[f(bb)]^(1/2)= 0.3 <em>(square root of f(bb)).</em>

Also, we can calculate the frequency of the B allele, as the probability of all alleles of the gene sum 1. In other words:

f(b)+f(B)=1 => f(B)=1 - f(b) = 1 - 0.3 = 0.7

So far, we have calculated the allelic frequencies, f(b)=0.3 and f(B)=0.7.

Now we can calculate the genotypic frequencies, using the equations of the Hardy-Weinberg equilibrium.

  • f(bb)=[f(b)]^2 => f(bb)=0.3^2=0.09
  • f(Bb)=2*f(B)*f(b) => f(Bb)=2*0.7*03=0.42
  • f(BB)=[f(B)]^2 => f(BB)=0.7^2=0.49

Finally, knowing that there are 4000 children in the next generation, to know how many of them are expected to be heterozygous for the eye colour, we should multiply the number of children for the probability of being heterozygous for the eye colour (which is the genotypic frequency for the genotype Bb).

  • Nº of heterozygous individuals = f(Bb)*total population= 0.42*4000
  • => Nº of heterozygous individuals =1680

<em />

3 0
3 years ago
What aspect of basterica makes recombainat dna technology effective?
Flura [38]
The answer is C. (The second B).

Because, Bacteria are key to recombinant DNA technology because of one simple fact. The reproduce rapidly.
6 0
3 years ago
WILL GICE BRAINLIEST!!
larisa86 [58]

The answer is; burning unleaded gasoline

Unleaded gasoline does not reduce carbon emissions. The lead was added to fuel ideally for vehicles to reduce the knocking of engines. Lead in its chemical structure also increased fuel octane levels. When lead was discovered to be a neurotoxin, it was banned as an additive in fuel in most countries.  


5 0
3 years ago
Which example represents a DISADVANTAGE of asexual reproduction?
Nookie1986 [14]
<span>B) A single antibiotic is able to quickly and easily kill millions of genetically identical bacteria
As they have reproduced Asexually they are all identical and can be wiped out easily.</span>
6 0
3 years ago
Read 2 more answers
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