Answer:
Step-by-step explanation:
Point P is on line segment
O
Q
‾
OQ
. Given
O
P
=
6
,
OP=6,
O
Q
=
4
x
−
3
,
OQ=4x−3, and
P
Q
=
3
x
,
PQ=3x, determine the numerical length of
O
Q
‾
.
OQ
.
Label known information:
Label known information:
O
P
Q
6
3x
OQ = 4x – 3
O
P
+
P
Q
=
OP+PQ=
O
Q
OQ
6
+
3
x
=
6+3x=
4
x
−
3
4x−3
−
4
x
−4x=
−
4
x
−4x
−
x
+
6
=
−x+6=
−
3
−3
−
6
−6=
−
6
−6
−
x
=
−x=
−
9
−9
−
x
−
1
=
−1
−x
=
−
9
−
1
−1
−9
x
=
x=
9
9
Plug in value of
x
to find
O
Q
:
Plug in value of x to find OQ:
O
Q
=
4
x
−
3
=
4
(
9
)
−
3
=
33
OQ=4x−3=4(9)−3=33
You can plug
x
into each expression:
You can plug x into each expression:
O
P
Q
6
3(9)
OQ = 4(9) – 3
Simplify:
Simplify:
O
P
Q
6
27
OQ = 33
Final Answer:
Final Answer:
O
Q
=
33
OQ=33
Answer: sin(FGE) = 9/15
Step-by-step explanation:
sine is opposite side over hypotenuse
angle FGE is opposite of side FE
Implicit differentiation: 2x+2ydy/dx-6-4dy/dx=0. When dy/dx=0, we have a horizontal tangent.
So 2x-6=0 and x=3. To find y we solve 9+y²-18-4y=-4, y²-4y-5=0=(y-5)(y+1), so the points are (3,5) and (3,-1).
2xdx/dy+2y-6dx/dy-4=0. When dx/dy=0 we have a vertical tangent, so 2y=4, y=2, and x²+4-6x-8=-4, x²-6x=0, x=0 and 6.
The points are (0,2) and (6,2).
Omg I need the same thing can someone help ??
