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3 years ago

Wright (3+4i)+(8+2i) as a complex number in standard form

Mathematics

2 answers:

Gnoma [55]3 years ago

6 0

Answer:

$= 11 + 6i$

Step-by-step explanation:

$(3 + 4i) + (8 + 2i) \\ 3 + 4i + 8 + 2i \\ = 11 + 6i$

hope this helps

brainliest appreciated

good luck! have a nice day!

Andrews [41]3 years ago

4 0

Answer:

11 +6i

Step-by-step explanation:

(3+4i)+(8+2i)

Add the real portions

3+8 = 11

Add the imaginary portions

4i+2i = 6i

The complex number in a+bi form is

11 +6i

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lys-0071 [83]

Reflection across the x-axis, followed by a, ?

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4 years ago

4x + 3(4x + 7) = 4(7x + 3)

Natasha2012 [34]

Answer: 1

Step-by-step explanation:4x + 3(4x + 7) = 4(7x + 3) + -3

Reorder the terms:

4x + 3(7 + 4x) = 4(7x + 3) + -3

4x + (7 * 3 + 4x * 3) = 4(7x + 3) + -3

4x + (21 + 12x) = 4(7x + 3) + -3

Reorder the terms:

21 + 4x + 12x = 4(7x + 3) + -3

Combine like terms: 4x + 12x = 16x

21 + 16x = 4(7x + 3) + -3

Reorder the terms:

21 + 16x = 4(3 + 7x) + -3

21 + 16x = (3 * 4 + 7x * 4) + -3

21 + 16x = (12 + 28x) + -3

Reorder the terms:

21 + 16x = 12 + -3 + 28x

Combine like terms: 12 + -3 = 9

21 + 16x = 9 + 28x

Solving

21 + 16x = 9 + 28x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-28x' to each side of the equation.

21 + 16x + -28x = 9 + 28x + -28x

Combine like terms: 16x + -28x = -12x

21 + -12x = 9 + 28x + -28x

Combine like terms: 28x + -28x = 0

21 + -12x = 9 + 0

21 + -12x = 9

Add '-21' to each side of the equation.

21 + -21 + -12x = 9 + -21

Combine like terms: 21 + -21 = 0

0 + -12x = 9 + -21

-12x = 9 + -21

Combine like terms: 9 + -21 = -12

-12x = -12

Divide each side by -12.

x = 1

Simplifying

x = 1

5 0

3 years ago

3×52 A. 5/6 B. 15/2 C.8/2 D.15/6

ohaa [14]

D.) 15/6

- 3 times 52 = 156, and since you can't exactly convert it to a fraction then i'm assuming that it is 'D'.

- Ouma :>

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3 years ago

De moirve's (√3-i ÷ √3+i)^6 = 1

bulgar [2K]

(√3 - i ) / (√3 + i ) × (√3 - i ) / (√3 - i ) = (√3 - i )² / ((√3)² - i ²)

… = ((√3)² - 2√3 i + i ²) / (3 - i ²)

… = (3 - 2√3 i - 1) / (3 - (-1))

… = (2 - 2√3 i ) / 4

… = 1/2 - √3/2 i

… = √((1/2)² + (-√3/2)²) exp(i arctan((-√3/2)/(1/2))

… = exp(i arctan(-√3))

… = exp(-i arctan(√3))

… = exp(-iπ/3)

By DeMoivre's theorem,

[(√3 - i ) / (√3 + i )]⁶ = exp(-6iπ/3) = exp(-2iπ) = 1

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3 years ago

Evaluate when n = 3. (244 − n)×n -3 9 55 72

HACTEHA [7]

Answer:

$(244 - n)n \\ n = 3 \\ (244 - 3) \times 3 \\ = (241) \times 3 \\ = 723$

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3 years ago