True because that’s how you look back on the data of the variables.
The question is incomplete as there is no options given;
the complete question with options is;
<span>Which column or columns in each table should be defined as the primary key?
</span>a.Orders: OrderID; OrderLineItems: OrderID, OrderSequence, andProductID; Products: ProductID and ProductName
b.Orders: OrderID; OrderLineItems: OrderID and OrderSequence;Products: ProductID
c.Orders: OrderID and OrderDate; OrderLineItems: OrderID andOrderSequence; Products: ProductID
d.Orders: OrderID; OrderLineItems: OrderID; Products: ProductID
Answer:
the correct option from the given options is, "b",Orders: OrderID; OrderLineItems: OrderID and OrderSequence;Products: ProductID
when you are going to create a primary key, <span>In Object Explorer, right-click the table to which you want to add a unique constraint, and then click Design. In Table Designer tab, click the row selector for the database </span>column<span> you want to define as the </span>primary key<span>.</span>
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
Answer:
Register-it contains all the instructions that are present in the processor.
Memory location- it is the particular memory address where the data is stored.
Explanation: Difference between register and memory location are as follows :-
- Register are the found in the CPU internal storage and memory location is present on the RAM.
- Registers are faster in movement as compared to the memory location.
- Register has the capacity of holding of less data as compared to the memory location which can store data in large amount .
Answer:
for numB in [5,8]:
for numA in [2,3]:
print(numB, numA)
Explanation:
Looking at the given output it can bee sent that the first numbers are repeated twice consecutively and the second numbers in a sequence.
This means that nested loops are used.
Assuming that the indentation will be correct in the program
The code in squence is:
for numB in [5,8]:
for numA in [2,3]:
print(numB, numA)