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mote1985 [20]
3 years ago
15

If David and jake each looked at a strand of their hair under a microscope measured the diameter jake strand was 0.005 cm in the

diameter David strand was 0.0012 cm in diameter
Mathematics
2 answers:
kakasveta [241]3 years ago
8 0

Answer:

=\frac{0.005}{0.0012}

= 4.17

\approx 4

Jake's strand represents 4 times David's strand.

Step-by-step explanation:

* microscope measured the diameter jake strand was 0.005 cm in the diameter

* David strand was 0.0012 cm in diameter

To find the ratio , we will have  to divide them

k=0.005cm and

d=0.0012cm

by dividing we get,

=\frac{0.005}{0.0012}

= 4.17

\approx 4

Therefore, Jake's strand represents 4 times David's strand.

Mama L [17]3 years ago
3 0

Answer:

<h2>Jake's strand represents 4 times David's strand.</h2>

Step-by-step explanation:

To find the ratio between these diameters, we just need to divide them

k=0.005cm and d=0.0012cm

If we divide

\frac{k}{d}=\frac{0.005}{0.0012} \approx 4

Therefore, Jake's strand represents 4 times David's strand.

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Answer:

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p_v =2*P(t_{(1699)}>1.971)=0.049  

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Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

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t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

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Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

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The first step is calculate the degrees of freedom, on this case:  

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Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

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