So hmm notice the first picture, that's the "inscribed angle theorem", as you'd know
now, notice angle 2 in yours on the second picture
Answer:
5 pizzas
Step-by-step explanation:
He will have $2.50 left over after he buys the 5 pizzas. Hope this helps! Brainliest is appriciated.
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
Answer:
2n(8n + 5)
Step-by-step explanation:
you need to see what you can take out of both the numbers.
ex they both have an 'n' and they both are divisible by 2
I can tell you that is 50 cents for cantaloupe at that price....
So I think he'd have to charge $1.50. He'd get what he paid for back plus a dollar. If C= one cantaloupe ....it would look something like
p > $1.50c
BECAUSE 1.50 x 14 = 21 minus the 7 he paid would leave you with 14... on dollar per cantaloupe... so the price can be anything greater than $1.50
