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hichkok12 [17]
4 years ago
8

Z to the power of 5 times z to the power of 6. this equation is exponets.

Mathematics
2 answers:
zheka24 [161]4 years ago
6 0

Answer:

z^11

Step-by-step explanation:

since both terms have "z" and the operation is multiplication, you <u>add</u><u> </u><u>the exponents</u><u> </u>together

Anna71 [15]4 years ago
5 0

Answer:

z^{11}

Step-by-step explanation:

If you are multiplying and have common base numbers or variables, add the powers together to solve. In this case, the common base variable is z.

z^{5} * z^{6}  = z^{5 + 6} = z^{11}

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Need help with this please
OLga [1]

Answer:

k= -2

Step-by-step explanation:

you are dividing the x by -2 each time

3 0
3 years ago
Given the following perfect square trinomial, fill in the missing term<br> 4x2 + ___x + 49
Arisa [49]

Answer:

wheres the square trinomail

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Determine the domain and range of the given function
Neporo4naja [7]

Answer:

List all of the solutions.

T

y

=

4

=

2

=

x

=

−

2

=

2

=

4

=

4

=

Step-by-step explanation:

3 0
3 years ago
. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 17m, diagonal QS
trapecia [35]

Answer:

495 meter²

Step-by-step explanation:

In the given kite QRST,

PQ = PS = 15 meter

QR = 17 meter

We have to find the area of the kite.

Since kite is in the form of a rhombus.

and rhombus is = \frac{1}{2}  (Diagonal QS) × (Diagonal RT)

In Δ QRP,

17² = 15² + RP²

\sqrt{17^{2}-15^{2}} = RP

RP=\sqrt{289-225}

= √64 = 8 meters.

So RT = RP + PT = 8 + 25 = 33 meter.

Now area of kite = \frac{1}{2} (30) (33) = 495 meter²

6 0
3 years ago
Find the value of x.<br><br> log 3 x = 4<br><br> A.) 7<br> B.) 12<br> C.) 27<br> D.) 81
lakkis [162]

Hello from MrBillDoesMath!

Answer:

Choice D, 81

Discussion:

By log 3x = 4 I presume that "3" is the base not a multiplier of x. Assuming it is the base, then the equation is equivalent to

x = 3^4

  = 81

This is Choice D.


Thank you,

MrB

8 0
3 years ago
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