Answer:
The answer is the third picture
Step-by-step explanation:
Answer:
Step-by-step explanation:
The formula for determining the volume of a cylinder is expressed as
Volume = πr²h
Where
r represents the radius of the cylinder.
h represents the height of the cylinder.
π is a constant whose value is 3.14
From the information given,
Height = 19 cm
Since the base area is 24π cm², we would determine its radius by applying the formula,
Area of circle = πr²
24π = πr²
r² = 24
r = √24
Therefore,
Volume of cylinder = π × (√24)² × 19 = 456π cm³
It is approximately
456 × 3.14 = 1431.8 cm³
Answer:
Correct answer: (a - 4) · (a + 6)
Step-by-step explanation:
Given:
a² - 4a - 24 + 6a = a² - 4a + 6a - 24 = a (a - 4) + 6 (a - 4) = (a - 4) · (a + 6)
God is with you!!!
Recall that

There are three cases to consider:
(1) When

, we have

and

, so

(2) When

and

, we get

and

, so

(3) When

, we have

and

, so

So