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3 years ago

7

Use the results about power series proved in this section to find values for

1 answer:

rewona [7]3 years ago

7 0

Yes they did i only want my points

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Identifying Rigid Transformations

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Answer:

Rotation and Translation

Step-by-step explanation:

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3 years ago

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G(n)=n^3+n<br> g(-3)<br> help!

Svetradugi [14.3K]

The question is simply asking you to evaluate the function for an input value of -3. Meaning we plug in -3 for all cases of n. (-3)^3 + (-3). This gives us -27 -3 which is -30. So g(-3)= -30

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3 years ago

Solve for y hdgkgsydkydutskgxtisit

Feliz [49]

You said X = (5y+1) / (y-2)

Multiply each side by (y-2):

X(y-2) = (5y+1)

Eliminate parentheses:

Xy - 2X = 5y + 1

Add 2X to each side:

Xy = 5y + 1 + 2X

Subtract 5y from each side:

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Divide each side by (X-5):

<em>y = (1+2X) / (X-5) </em>

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3 years ago

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PLEASE HURRY!!!!!!!!!!!!!!!!!

Scorpion4ik [409]

Answer:
6759
Step-by-step explanation:

y eso es

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2 years ago

Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the

sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let $y(t)$ be the depth of water in the barrel at time $t$ , where $y$ is measured in inches and $t$ in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

$\frac{dy}{dt}=-k\sqrt{y}$

where $k$ is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by $\frac{1}{\sqrt{y}}$

$\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k$

Multiply by $dt$

$\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt$

Take integral

$\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt$

Integrate

$2\sqrt{y}=-kt+C$

Isolate $y$

$y(t)=(\frac{C}{2} -\frac{k}{2}t)^2$

We know that the water level starts at 36, this means $y(0)=36$ . We use this information to find the value of $C$ .

$36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12$

$y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2$

At t = 1, y = 34

$34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}$

So our formula for the depth of water in the barrel is

$y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\$

To find the time, $t$ , at which all the water leaks out of the barrel, we solve the equation

$\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49$

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0

4 years ago