Given the following, use a pyagorean identity to find cos(0) if 0 is in quadrant IV.

Which components are a possible representation of vector w if the magnitude of vector -3w is ||-3w||=15?

Black_prince [1.1K]

Answer:

<-3,4>

<0,-5>

Step-by-step explanation:

|-3w| = 15

3|-w| = 3|w| = 15

|w| = $\frac{15}{3}$

|w| = 5

If vector w is represented by <1,-9>

Then |w| = $\sqrt{(1)^{2}+(-9)^{2}}=\sqrt{1+81}=\sqrt{82}\neq5$ .

Therefore this is not possible.

If vector w is represented by <-3,4>

Then |w| = $\sqrt{(-3)^{2}+(4)^{2}}=\sqrt{9+16}=\sqrt{25}=5$ .

Therefore this is possible.

If vector w is represented by <4,5>

Then |w| = $\sqrt{(4)^{2}+(5)^{2}}=\sqrt{16+25}=\sqrt{41}\neq5$ .

Therefore this is not possible.

If vector w is represented by <-5,-3>

Then |w| = $\sqrt{(-5)^{2}+(-3)^{2}}=\sqrt{25+9}=\sqrt{34}\neq5$ .

Therefore this is not possible.

If vector w is represented by <0,-5>

Then |w| = $\sqrt{(0)^{2}+(-5)^{2}}=\sqrt{0+25}=\sqrt{25}=5$ .

Therefore this is possible.

(NOTE : if z vector is represented by <x,y> then |z| = $\mathbf{\sqrt{x^{2}+y^{2}}}$ )

4 0

3 years ago

PLEASE HELP!! no links, no unnecessary comments or i will take away points. IF SHOWN ON PAPER I WILL GIVE BONUS POINTS AND BRAIN

Ghella [55]

Answer:

(-3.5, 2)

Step-by-step explanation:

If you were to graph all the other points it would look like the picture below, so to complete the rectangle it has to be (-3.5,2)

3 0

2 years ago

1 over 2 times t equals 3 over 4

lana66690 [7]

1/2t=3/4
I believe you need to find t here
So I would do 3/4/1/2 which would be 3/4*2/1
3/4*2/1= 6/4
6/4=3/2

8 0

3 years ago

Read 2 more answers

The average full-time faculty member in a college works an average of 53 hours per week. a) If we assume the standard deviation

arsen [322]

Answer:

2.28% of faculty members work more than 58.6 hours a week.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The average full-time faculty member in a college works an average of 53 hours per week. Standard deviation of 2.8 hours.

This means that $\mu = 53, \sigma = 2.8$