3 years ago

Evaluate 3(a-4b) when a= -2 and b= 5

Mathematics

1 answer:

pshichka [43]3 years ago

7 0

I believe the answer is -26 :) I hope this helps! ^_^

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I donot understand at all

loris [4]

Answer:

sorry i dont understand either!!!

Step-by-step explanation:

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3 years ago

What is the factor of: 3х^2+ 10x +7

JulijaS [17]

Answer:

(3x+7)(x+1)

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3 years ago

Find the length of the<br> missing side of the triangle<br> to the nearest tenth.

babymother [125]

Hey! So you’re gonna need to use the Pythagorean Theorem (a^2 + b^2 = c^2).
You’re looking for one of the legs here, so after inputting the values your equations should look like this: 6^2 + b^2 = 10^2.
Next, find what the numbers squared are: 36 + b^2 = 100.
Then, isolate the variable: b^2 = 64.
Lastly, square root both sides: √b^2 = √64.
You should find the answer is 8.

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3 years ago

Find the value of x to the nearest tenth will mark brainliest

Orlov [11]

Answer:

B. 5.4

Step-by-step explanation:

3/5 = 6/10

6/10 = 0.6

9 x 0.6 = 5.4

7 0

3 years ago

Write expression using a positive exponent<br />

GrogVix [38]

$a^{-n}=\dfrac{1}{a^n}\\\\4^{-1}=\dfrac{1}{4}\\\\5^{-3}=\dfrac{1}{5^3}\\\\-6^{-2}=-\dfrac{1}{6^2}\\\\-3^{-3}=-\dfrac{1}{3^3}\\\\3^{-5}=\dfrac{1}{3^5}\\\\10^{-4}=\dfrac{1}{10^4}\\\\p^{-1}=\dfrac{1}{p^1}\\\\a^{-10}=\dfrac{1}{a^{10}}\\\\d^{-3}=\dfrac{1}{d^3}\\\\q^{-4}=\dfrac{1}{q^4}\\\\b^{-15}=\dfrac{1}{b^{15}}\\\\r^{-20}=\dfrac{1}{r^{20}}$

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3 years ago