Answer:
<h2>x = 30°</h2>
Step-by-step explanation:
The angle 30° and 2x are complementary angles.
Two angles are called complementary angles, if their sum is one right angle (90°).
Therefore we have the equation:
30 + 2x = 90 <em>subtract 30 from both sides</em>
2x = 60 <em>divide both sides by 2</em>
x = 30
Answer:
y=-2/5x-3
Step-by-step explanation:
the slope is m and the y intercept is b
Answer:
Step-by-step explanation:
The diagram shows lines passing through the points of two equations.
We will determine the points through which the lines pass through on the graphs.
Looking at the line on the right hand side of the graph, the slope is
(y2-y1)/x(2-x1) where
y2= 0, y1 = 4
x2 = 3, x1=0
Slope, m = (0-4)/3-0
Slope = -4/3
Recall the equation of a straight line is y = mx + c
Where c is the intercept.
So the equation is y
y = -4x/3 + 4
Looking at the line on the left hand side of the graph, the slope is
(y2-y1)/x(2-x1) where
y2= 0, y1 = 2
x2 = -1, x1 =0
Slope, m = (0-2)/-1-0
Slope = -2/-1 = 2
Applying equation of a straight line is y = mx + c
The equation
y = 2x + 2
So the equations are
-4x/3 + 4. If x lesser than or equal 0
2x + 2. If x greater than 0
Answer:
the man is 52 years old
Step-by-step explanation:
man: 35+x
son:x
y=884/x
x(35+x)=884
35x+x^2=884
35x+x^2-884=884-884 . 884/-17+52=35
x^2+35x-884=0
(x-17)(x+52)=0
x=17 . x=-52 (age can't be negative)
man:35+17=52
Answer:
- x +y = 500
- 0.65x +0.95y = 0.75(500)
- solution: (x, y) = (300, 200)
Step-by-step explanation:
A system of equations for the problem can be written using the two given relationships between quantities of brass alloys.
<h3>Setup</h3>
Let x and y represent the quantities in grams of the 65% and 90% alloys used, respectively. There are two relations given in the problem statement.
x + y = 500 . . . . . . quantity of new alloy needed
0.65x +0.90y = 0.75(500) . . . . . quantity of copper in the new alloy
These are the desired system of equations.
<h3>Solution</h3>
This problem does not ask for the solution, but it is easily found using substitution for x.
x = 500 -y
0.65(500 -y) +0.90y = 0.75(500)
(0.90 -0.65)y = 500(0.75 -0.65) . . . . . . subtract 0.65(500)
y = 500(0.10/0.25) = 200
x = 500 -200 = 300
300 grams of 65% copper and 200 grams of 90% copper are needed.