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3 years ago

I don’t understand the question

Mathematics

1 answer:

Mariana [72]3 years ago

8 0

I can't see the question in the photo. Is it asking how many rotations the shape did?

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I need help with this please! ASAP<br> (PLEASE MULTIPLY AND SIMPLIFY COMPLETELY)

ivanzaharov [21]

Answer:

6/25

Step-by-step explanation:

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2 years ago

Read 2 more answers

Jody has 3 red marbles 7 blue marbles and 8 yellow marbles what is the ratio red to blue marbles

torisob [31]

Answer:

3/7

Step-by-step explanation:

The ratio is the number of red marbles and the number of blue marbles in a fraction, so the ratio would be 3/7

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3 years ago

Which of the following is the equation of a line that passes through the point (1,4) and is parallel to the x-axis?

Alexandra [31]

A because , well Y=4 and the points y coordinate is 4. And when a line is Y= a certain number, its a horizontal line parallel to x axis

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2 years ago

What is the difference between categorical and quantitative data? Give examples of each of your own for each. Also decide whethe

Snezhnost [94]

Categorical data may or may not have some logical order while the values of a quantitative variable can be ordered and measured.

Categorical data examples are: race, sex, age group, and educational level

Quantitative data examples are: heights of players on a football team; number of cars in each row of a parking lot

a) Colors of phone cover - quantitative

b) Weight of different phones - quantitative

c) Types of dogs - categorical

d) Temperatures in the U.S. cities - quantitative

6 0

2 years ago

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

3 years ago