Question

The perimeter of a square is 56cm. What is the approximate length of its diagonal?

Answer 1

To find the answer, we can use the Pythagoras theorem, where:

$\sqrt{a^{2}+ b^{2} } =c^{2}$

Where a and b is the side length and c is the diagonal.

In this case:

$\sqrt{56^{2} +56^{2} } \\ =\sqrt{6272} \\ =79.19596... \\ =79.2(correct to 3 sig. fig.)$

Therefore, the answer is 79.2cm

Hope it helps!