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Vikki [24]
3 years ago
15

Find the GCF of 28c-12

Mathematics
2 answers:
stira [4]3 years ago
5 0
THE GCF IS 4; I hope this helps
Bumek [7]3 years ago
3 0
The answer is four because you can divide both sides by 4
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If the angle m/_AEB=47 and angle m/_AEC=105 with the angle AE = 0, what is m/_BED
algol13

Answer:

80*

Step-by-step explanation:

8 0
3 years ago
What is the first step in order to solve the equation p-6.1=10 is it add 6.1 to the p -6.1 and add 10 to the 10 or is it another
MaRussiya [10]

Answer:

16.1

Step-by-step explanation:

p-6.1=10

p=6.1+10

p=16.1

5 0
3 years ago
Trigonometry: <br>1) Work out the bearing from B to C. <br>2) Calculate the bearing of D from B
kakasveta [241]

Answer:

see below

Step-by-step explanation:

a bearing is the angle in degrees measured clockwise from north.

Triangle ABC is a right triangle

Tan C = opp side / hyp

tan C = AB / CA

tan C = 30/30

tan C = 1

taking the inverse tan

tan ^ -1 tan C = tan ^ -1 ( 1)

C = 45 degrees

This is 90+45 degrees from North

135 degrees from north

Tan B = opp side / hyp

tan B = AD/BA

tan B = 45/30

tan B = 3/2

taking the inverse tan

tan ^ -1 tan B = tan ^ -1 ( 3/2)

D = 56.30993247

Add 180 degrees

180+56.30993247

236.3099325 from north

7 0
3 years ago
NEED HELP ASAP (will mark brainliest)
klemol [59]
Answer: 30 feet away
7 0
3 years ago
Read 2 more answers
nickel has an approximate diameter of 20 mm and an approximate thickness of 2 mm what is the approximate volume of a stack of 40
ziro4ka [17]

Answer:

The approximate volume of a stack of 40 nickels is 25132.741 cubic milimeters.

Step-by-step explanation:

A nickel can be modelled by the formula of a right cylinder, the approximate volume of the stack of nickels (V_{net}), measured in cubic milimeters, is the product of the number of elements (n), no unit, and the volume of each element (V), measured in cubic milimeters. That is:

V_{net} = n\cdot V (1)

By volume equation of right cylinder, we have the following formula:

V_{net} = \frac{\pi}{4}\cdot n \cdot D^{2}\cdot h (2)

Where:

n - Amount of nickels, no unit.

D - Diameter of nickel, measured in milimeters.

h - Thickness of nickel, measured in milimeters.

If we know that n = 40, D = 20\,mm and h = 2\,mm, then the net volume of the stack of nickels is:

V_{net} = \frac{\pi}{4}\cdot (40)\cdot (20\,mm)^{2}\cdot (2\,mm)

V_{net} \approx 25132.741\,mm^{3}

The approximate volume of a stack of 40 nickels is 25132.741 cubic milimeters.

8 0
3 years ago
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