So, the fact that it's a specific instrument doesn't change why you need to correct the data.
However, for this question it is important to know the instrumentation.
Since respirometers are measuring the <span>C<span>O2</span>:<span>O2</span></span><span> relation, clearly having biotic material and abiotic material will change the measurements.
You should be able to figure out that the general gas law is coming into effect because of the act of cellular respiration.
In general terms, you are correcting your instrument to a known blank (you do this with scales and every other instrument).
By determining the reading for the blank (marbles) you can know the relative error of the instrument.
Taking a scale for example: You 0 the scale to a mass of importance (the amount of error you're okay with) and then use it for your measurements so you can be adequately confident of the mass you're measuring .</span>
Answer:
The defective cell is the M cell. due to the stimulation of Hormone A, cell M produces hormone B in large quantities by inhibiting the production of hormone A by cell D
Answer:
Low-pressure areas are places where the atmosphere is relatively thin. Winds blow inward toward these areas. This causes air to rise, producing clouds and condensation. Low-pressure areas tend to be well-organized storms.
Answer: The order is a-b-c-d-e-
Explanation:
In winter there is a thin layer of ice that covers the water of the lakes below. As spring approaches (a) surface water warms to 4 C and sinks. This eliminates the thermal stratification and (b) water mixes, bringing oxygen to the bottom and nutrients to the surface. In Summer, the lake presents again a clear thermocline profile as (c) warm surface water is separated from cooler bottom water. In the fall, (d) surface water cools to 4 C and sinks. This causes the lake water to mix once more (e) bringing oxygen to the bottom and nutrients to the surface.
Answer:
After this treatment, the investigators should expect to get a mixture of the desired enzyme, plus fragments of the peptide used to desorb the enzyme in question.
This would be the result of using a peptide as a desorption solution when the desired protein is a protease,
Assuming that the protease retains its activity in the medium in question, and that the peptide can act as a substrate (which would make sense), as the peptide solution is added, it will interact with and bind to the antibody, but some molecules will also interact with the active site of the enzyme as it desorbs and passes through, culminating on the elution of the hydrolized part of the peptide along with the enzyme.