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4 years ago

I really need help please

Mathematics

2 answers:

Citrus2011 [14]4 years ago

7 0

Answer:

∠ A = 60°

Step-by-step explanation:

Using the sine ratio in the right triangle

sinA = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AC}$ = $\frac{13}{15}$ , thus

∠ A = $sin^{-1}$ ( $\frac{13}{15}$ ) ≈ 60°

------------------------------------------------

Using the cosine ratio in the right triangle

cosR = $\frac{adjacent}{hypotenuse}$ = $\frac{RT}{RS}$ = $\frac{8}{10}$ , thus

∠ R = $cos^{-1}$ ( $\frac{8}{10}$ ) ≈ 36.9° ( to 1 dec. places )

andrew11 [14]4 years ago

3 0

Answer:look at step by step

Step-by-step explanation:how do I post questions and I’ll help you

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Answer:

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Read 2 more answers

Give three points that lie on a line with a<br>slope of -2/5

Luda [366]

Answer:

The three points that lie on a line y = -2/5x with a slope -2/5 will be:

(0, 0)

(5, -2)

(10, -4)

Please check the attached graph also.

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

$y = mx+b$

where m is the slope and b is the y-intercept

Given

slope = m = -2/5

We suppose the line passes through the origin.

so b = 0

substituting m = -2/5 and b = 0 in the slope-intercept form

$y = mx+b$

y = -2/5x + 0

y = -2/5x

Thus, the equation of line with the slope m = -2/5 and passes through the origin (0, 0) will be:

y = -2/5x

As the equation of line passes through (0, 0), thus the point (0, 0) lies on the line.

Putting x = 0 in the equation y = -2/5x

y = -2/5 × (0)

y = 0

Thus, (0, 0) is the point which also passes through the line

Putting x = 5 in the equation y = -2/5x

y = -2/5 × 5

y = -2

Thus, (5, -2) is the point which also passes through the line

Now, putting x = 10 in the equation y = -2/5x

y = -2/5 × 10

y = -4

Thus, (10, -4) is the point which also passes through the line.

Thus, the three points that lie on a line y = -2/5x with a slope -2/5 will be:

(0, 0)

(5, -2)

(10, -4)

Please check the attached graph also.

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